3w^2=558

Solution for 3w^2=558 equation:

3w^2=558

We move all terms to the left:

3w^2-(558)=0

a = 3; b = 0; c = -558;
Δ = b2-4ac
Δ = 02-4·3·(-558)
Δ = 6696
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{6696}=\sqrt{36*186}=\sqrt{36}*\sqrt{186}=6\sqrt{186}$
$w_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-6\sqrt{186}}{2*3}=\frac{0-6\sqrt{186}}{6}
=-\frac{6\sqrt{186}}{6}
=-\sqrt{186}
$
$w_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+6\sqrt{186}}{2*3}=\frac{0+6\sqrt{186}}{6}
=\frac{6\sqrt{186}}{6}
=\sqrt{186}
$